If we need a magnification of 375 from a compound microscope of tube length 150 mm and an objective of focal length 5 mm, the focal length of the eye-piece, should be close to :
Text Solution
Verified by ExpertsThe correct answer is:
D
Case-I
If final image is at least distance of clear visio
M.P. = 
; 375 = 
f e = 
= 2.17 cm; f e ≈ 22 mm
Case-II
If final image is at infinity ;
M.P. = 
= 375
f e = 22 mm
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